Re: How to calculate Local DOS (not PDOS) ( No.1 ) |
- Date: 2022/09/09 15:12
- Name: Naoya Yamaguchi
- Hi,
This kind of LDOS has several definitions: for example, https://doi.org/10.1103/PhysRevB.63.115314 . However, a common feature is that the LDOS can be obtained from the eigenvalues and Kohn-Sham orbitals, although the definition is different. Therefore, you can get the LDOS according to Eq. 1 in the paper you suggested from the eigenvalues and MOs in the OpenMX.
Regards, Naoya Yamaguchi
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Re: How to calculate Local DOS (not PDOS) ( No.2 ) |
- Date: 2022/09/15 15:24
- Name: T. Ozaki
- Hi,
By summing all the contributions of PDOS in each layer, one can calculate the PDOS (equivalently LDOS) resolved to layer. The data of Fig. 8 in a paper: https://doi.org/10.1103/PhysRevB.81.115444 was calculated by the way.
Regards,
TO
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