Re: How does openMX decide the number of eigenvalues on a Kpoint (number of bands) and valance bands ( No.1 ) |
- Date: 2023/05/18 12:46
- Name: Naoya Yamaguchi
- Hi,
As for the first question, the number of the occupied bands has to be 22 in this case. Where did you find "28"?
>Second, According to number of basis, (3*1+2*3+5*2+7*1)*5=130. This is equal to the total number of all bands. it seems indicate that the number of whole bands are decided by the number of basis functions.
Yes.
Regards, Naoya Yamaguchi
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Re: How does openMX decide the number of eigenvalues on a Kpoint (number of bands) and valance bands ( No.2 ) |
- Date: 2023/05/18 12:52
- Name: Naoya Yamaguchi
- Dear Tao Zhang,
I've understood what you mean about "28". Since the Fermi level is not set to 0 eV, you should compare the energy eigenvalues with the chemical potential of -0.184138965809156. You can find that the number of valence bands is 22 from that.
Regards, Naoya Yamaguchi
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Re: How does openMX decide the number of eigenvalues on a Kpoint (number of bands) and valance bands ( No.3 ) |
- Date: 2023/05/18 17:44
- Name: Tao Zhang <zhangtao_scu@outlook.com>
- Hi
Oh, I get iy. Sorry for I forget that. many thanks for your guidance.
Best regards, Tao
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