Re: Electric polarization of BiFeO3 (procedure in obtaining net polarization) ( No.1 ) |
- Date: 2024/10/30 14:29
- Name: Naoya Yamaguchi
- Dear Amran-san,
It is not clear what the circumstances are since the original case was not left in the previous thread, but my explanation of the earlier discussion seems to lack generality, but basically there is a 2ƒÎ arbitrariness in the inner product of the reciprocal lattice vector and the electronic contribution to the electric polarization: G_iEP_e=2ƒÎe/V, that is, (R_j~R_k)/|R_j~R_k|EP_e=e/|R_j~R_k|=e|R_i||cosƒÆ|/V, where ƒÆ is the angle between R_i and R_j~R_k.
Also, the electric polarization in solids can be well defined only by its difference.
Regards, Naoya Yamaguchi
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Re: Electric polarization of BiFeO3 (procedure in obtaining net polarization) ( No.2 ) |
- Date: 2024/10/31 15:54
- Name: Amran Yatmeidhy
- Dear Yamaguchi-san,
Thank you for your response. Here is the calculation results comparing ferroelectric and paraelectric phases of BiFeO3:
1) Ferroelectric (I use slightly different atomic position than I previously posted)
*************************************************************** Electric polarization (muC/cm^2) : Berry phase ***************************************************************
Background Core Electron Total
Px -0.00000000 -0.00000000 -0.00000096 -0.00000096 Py -0.00000000 0.00000000 -0.00000018 -0.00000018 Pz -0.00000000 7473.32992459 23.97013715 7497.30006174
cell structure: Atoms.SpeciesAndCoordinates.Unit Frac # Ang|AU <Atoms.SpeciesAndCoordinates 1 Bi 0.0000000000000000 0.0000000000000000 0.0000000000000000 7.5 7.5 off 2 Bi 0.5000000000000000 0.5000000000000000 0.5000000000000000 7.5 7.5 off 3 Fe 0.2233892803913956 0.2233892803913956 0.2233892803913956 10.5 5.5 off 4 Fe 0.7233892803913956 0.7233892803913956 0.7233892803913956 5.5 10.5 off 5 O 0.8820430721883523 0.4365085820904617 0.0387306473898750 3.0 3.0 off 6 O 0.4365085820904617 0.0387306473898750 0.8820430721883523 3.0 3.0 off 7 O 0.0387306473898750 0.8820430721883523 0.4365085820904617 3.0 3.0 off 8 O 0.9365085820904617 0.3820430721883524 0.5387306473898750 3.0 3.0 off 9 O 0.5387306473898750 0.9365085820904617 0.3820430721883524 3.0 3.0 off 10 O 0.3820430721883524 0.5387306473898750 0.9365085820904617 3.0 3.0 off Atoms.SpeciesAndCoordinates> Atoms.UnitVectors.Unit Ang # Ang|AU <Atoms.UnitVectors 2.7903465736272248 1.6110073454160283 4.6799943377191253 -2.7903465736272248 1.6110073454160283 4.6799943377191253 0.0000000000000000 -3.2220146908320566 4.6799943377191253 Atoms.UnitVectors>
2) Paraelectric
*************************************************************** Electric polarization (muC/cm^2) : Berry phase ***************************************************************
Background Core Electron Total
Px -0.00000000 0.00000000 -0.00000007 -0.00000007 Py -0.00000000 0.00000000 0.00000000 0.00000000 Pz -0.00000000 6861.03272492 -0.00000000 6861.03272492
cell structure: Atoms.SpeciesAndCoordinates.Unit Frac # Ang|AU <Atoms.SpeciesAndCoordinates 1 Bi 0.0000000000000000 0.0000000000000000 0.0000000000000000 7.5 7.5 off 2 Bi 0.5000000000000000 0.5000000000000000 0.5000000000000000 7.5 7.5 off 3 Fe 0.2500000000000000 0.2500000000000000 0.2500000000000000 10.5 5.5 off 4 Fe 0.7500000000000000 0.7500000000000000 0.7500000000000000 5.5 10.5 off 5 O 0.9185700000000000 0.5000000000000000 0.0814300000000000 3.0 3.0 off 6 O 0.5000000000000000 0.0814300000000000 0.9185700000000000 3.0 3.0 off 7 O 0.0814300000000000 0.9185700000000000 0.5000000000000000 3.0 3.0 off 8 O 0.0000000000000000 0.4185700000000000 0.5814300000000000 3.0 3.0 off 9 O 0.5814300000000000 0.0000000000000000 0.4185700000000000 3.0 3.0 off 10 O 0.4185700000000000 0.5814300000000000 0.0000000000000000 3.0 3.0 off Atoms.SpeciesAndCoordinates> Atoms.UnitVectors.Unit Ang # Ang|AU <Atoms.UnitVectors 2.7903465736272248 1.6110073454160283 4.6799943377191253 -2.7903465736272248 1.6110073454160283 4.6799943377191253 0.0000000000000000 -3.2220146908320566 4.6799943377191253 Atoms.UnitVectors>
If I just simply take the difference of the total polarization of the two phases, I got 636.27 muC/cm^2. And considering the quantum polarization, the net polarization will be 106.04 muC/cm^2. Is this correct?
PS: the results I got from VASP calculation is about 103.12 muC/cm^2.
Sincerely, Amran
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Re: Electric polarization of BiFeO3 (procedure in obtaining net polarization) ( No.3 ) |
- Date: 2024/10/31 22:31
- Name: Naoya Yamaguchi
- Dear Amran-san,
As the calculation process is not written, it is hard to say, but if the calculated value matches the reference value well, I think it is probably correct.
Regards, Naoya Yamaguchi
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Re: Electric polarization of BiFeO3 (procedure in obtaining net polarization) ( No.4 ) |
- Date: 2024/11/01 13:09
- Name: Amran Yatmeidhy
- Dear Yamaguchi-san,
> And considering the quantum polarization, the net polarization will be 106.04 muC/cm^2.
I just divided 636.27 muC/cm^2 by 6 (~lattice = 5.68 Å).
Could you explain how to handle quantum polarization in openmx? (in step by step manner)
(In vasp, quantum polarization = integer * lattice)
Sincerely, Amran
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Re: Electric polarization of BiFeO3 (procedure in obtaining net polarization) ( No.5 ) |
- Date: 2024/11/01 21:56
- Name: Naoya Yamaguchi
- Dear Amran-san,
I was a little confused, but it seems that my explanation in the previous thread was based on eR_i/V and was correct. I was stuck with the notation in k-space, but indeed, it seems that eR_i/V is simply fine, since P_e is a quantum of eR_i/V from G_i P_e=2ƒÎe/V. Since polB up to 3.8 calculated the quantum of electric polarization as follows, after I commented it out, it was released without any modification as it was, so 3.9 does not output anything. However, it is something that should be corrected.
``` Parb[i] = AU2Mucm*2.0*PI/Gabs[i]/Cell_Volume ```
>I just divided 636.27 muC/cm^2 by 6 (~lattice = 5.68 Å).
At the very least, if 636.27 is the difference between the two phase values, I don't see the point of your process. It would be better to study "the modern theory of polarization". Instead, An integer multiple of eR_i/V should be added.
Regards, Naoya Yamaguchi
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